Re: Problema su teoria cinetica dei gas

From: Luca <carlonluca_at_supereva.it>
Date: Tue, 15 Jan 2002 22:41:59 GMT

"Gabriele De Chiara" <Gadec_at_katamail.com> wrote in message
news:a1sj5o$ut3$1_at_newsreader.mailgate.org...
> > P1/P2=T1/T2
> in questa giusta formula le temperature sono espresse in gradi kelvin
> mentre tu hai usato gradi celsius

P2 = (180*10^3*(384+273.15)K)/(27+275.15)K = 394092.953523.......Pa

Luca Carlon
Received on Tue Jan 15 2002 - 23:41:59 CET