Tom Roberts alle ore 08:47:53 del 04/08/2017 ha scritto:
> Your "quiet" is a HIGHLY unusual phasing. I assume that when you say "quiet"
> you mean that S is at rest in the same inertial frame as earth. Compared to
> the traveling twin, the earth and S are accurately at rest in an inertial
> frame. When you say "zero time" for both earth and S, I assume that the
> earth and S clocks are synchronized in their inertial frame (i.e. they both
> display that frame's time coordinate, for which t=0 at the traveling twin's
> departure).
>
> The general formula for elapsed proper time of an object moving relative to
> an inertial frame is:
> T_obj = \integral dt / gamma(v)
> where the integral is taken over the path of the moving object, v is its
> speed relative to the frame (as a function of t), t is the time coordinate
> of the frame, and gamma(v)=1/sqrt(1-v^2/c^2).
>
> So in the above formula, T=5 years, and gamma(v)=8. Since gamma(v) is
> constant the integral is trivial, with result
> t_elapsed = 5 years * 8 = 40 years.
>
> t_elapsed is the elapsed time in the inertial frame, which is also the value
> of the clock at S.
>
> Tom Roberts
But even the ship's reference is inertial because after the initial
acceleration it travels for 5 years with out-of-engine engines.
(Però anche il riferimento dell'astronave è inerziale perché dopo
l'iniziale accelerazione viaggia per 5 anni a motori spenti).
Luigi.
--
Luigi Fortunati
Credere e' piu' facile che pensare
Believing is easier than thinking
Received on Fri Aug 04 2017 - 20:04:32 CEST