Sylvia Else alle ore 09:29:47 del 04/08/2017 ha scritto:
>> Space station S is positioned at several light years away and is quiet
>> with Earth T:
>>
>> T ---------------------------------------- S -> x
>>
>> Since T and S are in quiet, Earth time is identical to that of the space
>> station.
>
> Presumably the intent is that S is at rest relative to Earth. They have
> to be rather more than "several" light years apart to make this work,
> since a gamma of 8 implies a velocity in excess of 99% of the speed of
> light, so the separation between S and the Earth has to be a little less
> than 40 light years.
>
>>
>> The traveling twin starts at zero time of all the clocks, travels to
>> gamma=8 and arrives in S when his watch marks the time of 5 years.
>
> This is a problematic statement, since it implies that the twin is not
> moving relative to Earth, otherwise the space station clock will not
> show zero in the frame of the twin. However, if we take it that this
> describes the situation just before the twin rapidly accelerates to the
> required velocity, then it makes sense.
>
>>
>> What time does the space station clock mark?
>>
>
> When the twin arrives at S, the space station clock will show 40.
>
> Sylvia.
Per il gemello viaggiatore è la Terra T che s'allontana e la stazione
spaziale S che s'avvicina mentre lui è immobile.
Quindi nel suo riferimento il tempo dilatato è quello di T e di S,
non il suo.
Inoltre non c'è alcuna inversione di marcia.
Luigi.
(For the traveling twin is the Earth T that is far behind and the space
station S approaching while he is motionless. So in its reference the
dilated time is that of T and S, not its own. There is also no
reversal).
--
Luigi Fortunati
Credere e' piu' facile che pensare
Believing is easier than thinking
Received on Fri Aug 04 2017 - 19:36:24 CEST