Re: tensore di Riemann

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From: Valter Moretti <vmoretti2_at_hotmail.com>
Date: Mon, 26 Jan 2009 08:02:07 -0800 (PST)

On Jan 26, 4:00 pm, Valter Moretti <vmoret..._at_hotmail.com> wrote:

> (2) come forma quadratica da V cartesiano V in R (quindi un tensore in
> VxV )

Riciao,
scusa sopra volevo scrivere .

...quindi un tensore in V*x V*

ovviamente!

Ciao, Valter
Received on Mon Jan 26 2009 - 17:02:07 CET

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